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Let Rbe a relation defined by R1 = {(a, b ) | a ≥ b, a, b ∈ R}. Then R1 is
  • a)
    an equivalence relation on R
  • b)
    reflexive, transitive but not symmetric
  • c)
    symmetric, transitive but not reflexive
  • d)
    neither transitive nor reflexive but symmetric
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let R1be a relation defined by R1= {(a, b ) | a ≥ b, a, b ∈ R}...
For any a ∈ R, we haye a ≥ a. Therefore, the relation R is reflexive but it is hot symmetric as (2, 1) ∈ R but (1, 2) ∉ R. The relation R is transitive also, because (a, b) ∈ R, (b, c) ∈ R imply that a ≥ b and b ≥. c which is turn imply that a ≥ c.
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Most Upvoted Answer
Let R1be a relation defined by R1= {(a, b ) | a ≥ b, a, b ∈ R}...
The relation R1 is defined as the set of ordered pairs (a, b) where a is less than or equal to b.
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Let R1be a relation defined by R1= {(a, b ) | a ≥ b, a, b ∈ R}...
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Let R1be a relation defined by R1= {(a, b ) | a ≥ b, a, b ∈ R}. Then R1 isa)an equivalence relation on Rb)reflexive, transitive but not symmetricc)symmetric, transitive but not reflexived)neither transitive nor reflexive but symmetricCorrect answer is option 'B'. Can you explain this answer?
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